<<echo=FALSE, results=hide>>=
sc <- NULL
while(is.null(sc)) {
p <- c(sample(1:3, 1), sample(1:5, 1))
q <- c(sample(4:5, 1), sample((1:5)[-p[2]], 1))
sol <- sqrt(sum((p - q)^2))

err <- c(sqrt(sum((p + q)^2)), sqrt(sum(abs(p - q))))
err <- err[abs(err - sol) > 0.1]
if(length(err) > 1) err <- sample(err, 1)

sc <- num_to_schoice(sol, wrong = err, range = c(0.1, 10), delta = 0.3, digits = 3)
}
@

\begin{question}
What is the distance between the two points
$p = (\Sexpr{p[1]}, \Sexpr{p[2]})$ and $q = (\Sexpr{q[1]}, \Sexpr{q[2]})$
in a Cartesian coordinate system?

<<echo=FALSE, results=tex>>=
answerlist(sc$questions)
@
\end{question}

\begin{solution}
The distance $d$ of $p$ and $q$ is given by
$d^2 = (p_1 - q_1)^2 + (p_2 - q_2)^2$ (Pythagorean formula).

Hence $d = \sqrt{(p_1 - q_1)^2 + (p_2 - q_2)^2} =
  \sqrt{(\Sexpr{p[1]} - \Sexpr{q[1]})^2 + (\Sexpr{p[2]} - \Sexpr{q[2]})^2}
   = \Sexpr{round(sol, digits = 3)}$.

<<echo=FALSE, results=hide, fig=TRUE>>=
par(mar = c(4, 4, 1, 1))
plot(0, type = "n", xlim = c(0, 6), ylim = c(0, 6), xlab = "x", ylab = "y")
grid(col = "slategray")
points(rbind(p, q), pch = 19)
text(rbind(p, q), c("p", "q"), pos = c(2, 4))
lines(rbind(p, q))
lines(c(p[1], p[1], q[1]), c(p[2], q[2], q[2]), lty = 2)
@

<<echo=FALSE, results=tex>>=
answerlist(ifelse(sc$solutions, "True", "False"))
@
\end{solution}

%% \extype{schoice}
%% \exsolution{\Sexpr{mchoice2string(sc$solutions)}}
%% \exname{Euclidean distance}