Exam 1

  1. Question

    Given the following information:

    banana ++ pineapple ++ banana = 564564
    banana ++ pineapple ++ pineapple = 873873
    orange ++ pineapple ++ pineapple = 864864

    Compute:

    banana ++ orange ++ pineapple = ?\text{?}

    1. 394394
    2. 555555
    3. 507507
    4. 873873
    5. 594594

    Solution

    The information provided can be interpreted as the price for three fruit baskets with different combinations of the three fruits. This corresponds to a system of linear equations where the price of the three fruits is the vector of unknowns xx:

    x1=x_1 = banana x2=x_2 = orange x3=x_3 = pineapple

    The system of linear equations is then: (201102012)(x1x2x3)=(564873864) \begin{aligned} \left( \begin{array}{rrr} 2 & 0 & 1 \\ 1 & 0 & 2 \\ 0 & 1 & 2 \end{array} \right) \cdot \left( \begin{array}{r} x_1 \\ x_2 \\ x_3 \end{array} \right) & = & \left( \begin{array}{r} 564 \\ 873 \\ 864 \end{array} \right) \end{aligned} This can be solved using any solution algorithm, e.g., elimination: x1=85,x2=76,x3=394. x_1 = 85, \, x_2 = 76, \, x_3 = 394. Based on the three prices for the different fruits it is straightforward to compute the total price of the fourth fruit basket via:

    banana ++ orange ++ pineapple =
    x1x_1 ++ x2x_2 ++ x3x_3 =
    8585 ++ 7676 ++ 394394 = 555555

    1. False
    2. True
    3. False
    4. False
    5. False